It is given that
\[
63.63=m\left(21+\frac{n}{100}\right)
\]
Where $ m, n $ are positive integers and $ n<100 . $ Find the value of $ m+n $

Given that
$63.63=m(21+\frac{n}{100})$
where $(m, n)$  are positive integers and $n<100$.

To find the value of $( m+n)$

Solution:

We know that

$63.63\div3 = 21.21 = 21 + \frac{21}{100}$ or

$63.63 = 3(21 +\frac{21}{100})$

Comparing to 

$63.63=m(21+\frac{n}{100})$

$m = 3$ and $n = 21$

So $m + n = 3 + 21 = 24$ or

So $(m + n) = 24$