It is given that 65610 is divisible by 27. Which two numbers nearest to 65610 are each divisible by 27?
Given:
65610 is divisible by 27.
To do:
We have to find the two nearest numbers to 65610 which are divisible by 27.
Solution:
If 65610 is divisible by 27 then 27 is a factor of 65610.
This implies,
If we add and subtract 27 from the given number the resulting numbers will also be divisible by 27.
$65610-27=65583$ and $65610+27=65637$
 Therefore,
$65583$ and $65637$ are the nearest numbers to 65610 which are divisible by 27.
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