Ishita invested Rs. 1,20,000 a part of it at 10% per annum and the remaining at 12% simple interest . Her annual income from these investment is Rs. 12800 , find the amount invested in each case .
Given:
Ishita invested Rs. 1,20,000 a part of it at 10% per annum and the remaining at 12% simple interest.
Her annual income from these investment is Rs. 12800.
To do: To find out the amount invested in each case.
Solution:
Let us assume Rs.$x$ was invested at $10%$
So, Rs.$(12000−x)$ was invested @ $12%$.
In one year she will earn an interest=
$x\times10%+(12000−x)\times12%=1280$
⇒$12000\times12%−x\times2%=1280$
⇒$12000\times12−x\times2=128000$
⇒$2x=144000−128000=16000$
⇒$x=8000$
So, Rs.$8000$ was invested at $10%$
Rs.$(12000−8000)=Rs.4000$ was invested @$12%$.
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