In triangle ABC, angle A is equal to 44°. If AB is equal to AC, find angle B and angle C.
Given:
In triangle ABC , $\angle$A = 44°.
AB = AC
To find:
We have to find $\angle$B and $\angle$C.
Solution:
If two sides of a triangle are equal, then it is an isosceles triangle. So, the
corresponding angles are also equal.
$\angle$B = $\angle$C.
Apply angle sum property,
Sum of angles of triangle = 180°
$\angle$ A + $\angle$ B + $\angle$ C = 180°
44°+ $\angle$B + $\angle$C = 180°
$\angle$ B + $\angle$C = $180° - 44°$
$\angle$B + $\angle$ C = 136°
$\angle$ B = $\angle$ C.
So,
$\angle$ B + $\angle$ B = 136°
2 $\angle$ B = 136°
$\angle$ B = $\frac{136}{2}$
$\angle$ B = 68°
Therefore,
$\angle$ B = 68°
$\angle$ C = 68°
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