In transferring $ 1.5 \mathrm{C} $ charge through a wire, $ 9 \mathrm{~J} $ of work is needed. Find the potential difference across the wire.
Given,
Charge, Q = 1.5C
Work done, W = 9J
To find - V, Potential difference (Voltage)
Solution-
We know that-
$V=\frac{W}{Q}$
Substituting the given values we get-
$V=\frac{9}{1.5}$
$V=\frac{90}{15}$
$V=6volt$
Hence, the potential difference across the wire will be 6V.
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