In the two 'set-ups' X and Y, shown on the next page, the wires AB and PQR are made of the same material and have equal thickness. The length of the wire AB, (in the set-up 'X') is equal to the diameter (= PR) of the semi-circle, formed by the wire PQR, (in the set-up 'Y'). Pins, P1 and P2, are attached, to wires AB and PQR respectively, with the help of wax. Which of the two pins, Pl or P2, will fall off later? Give reason for your answer.​"

Since, in 'Y' setup pin the length of the wire $PQR$ is more than the length of the wire $AB$ in 'X' setup. 

Therefore, pin P1 is much closer than pin P2 from the flame. So the heat will reach much earlier to pin P1 in 'X' setup than pin P2 in 'Y' setup.

Therefore, the wax in 'X' setup will melt much earlier than in 'Y' setup. 

That's why pin P2 will fall off later.

 

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Updated on: 10-Oct-2022

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