In the reaction represented by the following equation: CuO (s) + H2 (g) -------> Cu (s) + H2O (l)(a) name the substance oxidised (b) name the substance reduced (c) name the oxidising agent (d) name the reducing agent
$CuO\ +\ H_{2}\xrightarrow{Heat} \ Cu\ +\ H_{2} O$
(a) Hydrogen (H2) is oxidised.
(b) Copper oxide (CuO) is reduced.
(c) Copper oxide (CuO) is the oxidising agent.
(d) Hydrogen (H2) is the reducing agent.
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