In the given figure, $PR>PQ$ and PS bisects $\angle QPR$. Prove that $ \angle P S R>\angle P S Q $.
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Given:

$PR>PQ$ and PS bisects $\angle QPR$.

To do:

We have to prove that \( \angle P S R>\angle P S Q \).

Solution:

We know that,

Angle opposite to the larger side is greater angle.

This implies,

\( \angle P Q R>\angle P R Q \)

\( \angle Q P S=\angle R P S \)    (PS bisects $\angle QPR$)

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Updated on: 10-Oct-2022

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