In the given figure, find $ x $.
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Given:

The three angles of the given triangle are $5x-60^o$, $2x+40^o$ and $3x-80^o$.

To do:

We have to find the value of $x$.

Solution:

We know that,

Sum of the angles in a triangle is $180^o$.

Therefore,

$5x-60^o+2x+40^o+3x-80^o=180^o$

$10x=180^o+100^o$

$10x=280^o$

$x=\frac{280^o}{10}$

$x=28^o$

The value of $x$ is $28^o$.

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Updated on: 10-Oct-2022

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