In the following, determine whether the given values are solutions of the given equation or not:
$x^2\ +\ x\ +\ 1\ =\ 0,\ x\ =\ 0,\ x\ =\ 1$

Given:

The given equation is $x^2\ +\ x\ +\ 1\ =\ 0$.

To do:

We have to determine whether $x=0, x=1$ are solutions of the given equation.

Solution:

If the given values are the solutions of the given equation then they should satisfy the given equation.

Therefore,

For $x=0$,

LHS$=x^2+x+1$

        $=(0)^2+0+1$

        $=0+1$

       $=1$

RHS$=0$

LHS$≠$RHS

Hence, $x=0$ is not a solution of the given equation.

For $x=1$,

LHS$=x^2+x+1$

        $=(1)^2+1+1$

        $=1+1+1$

        $=3$

RHS$=0$

LHS$≠$RHS

Hence, $x=1$ is not a solution of the given equation.

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Updated on: 10-Oct-2022

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