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In the figure, POS is a line, find $x$."
Given:
POS is a line.
To do:
We have to find the value of $x$.
Solution:
We know that,
Sum of the angles on a straight line is $180^o$.
Therefore,
From the figure,
$\angle POQ + \angle QOR + \angle ROS = 180^o$
$60^o + 4x^o + 60^o = 180^o$
$4x = 180^o - 120^o$
$4x= 60^o$
$x = 15^o$
The value of $x$ is $15^o$.
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