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In the figure, if $l \parallel m \parallel n$ and $\angle 1 = 60^o$, find $\angle 2$."


Given:

$l \parallel m \parallel n$ and $\angle 1 = 60^o$
To do:

We have to find $\angle 2$.

Solution:

From the figure,

Transversal $p$ intersects lines $l, m$ and $n$.

$\angle 1 = 60^o$

$\angle 3 = \angle 1 = 60^o$              (Corresponding angles are equal)

$\angle 3 + \angle 4 = 180^o$          (Linear pair)

$60^o + \angle 4 = 180^o$

$\angle 4 = 180^o - 60^o$

$\angle 4 = 120^o$

$\angle 2 = \angle 4 = 120^o$                     (Alternate angles are equal)

Hence, $\angle 2 =120^o$.

Updated on: 10-Oct-2022

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