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In the figure, if $l \parallel m \parallel n$ and $\angle 1 = 60^o$, find $\angle 2$."
Given:
$l \parallel m \parallel n$ and $\angle 1 = 60^o$
To do:
We have to find $\angle 2$.
Solution:
From the figure,
Transversal $p$ intersects lines $l, m$ and $n$.
$\angle 1 = 60^o$
$\angle 3 = \angle 1 = 60^o$ (Corresponding angles are equal)
$\angle 3 + \angle 4 = 180^o$ (Linear pair)
$60^o + \angle 4 = 180^o$
$\angle 4 = 180^o - 60^o$
$\angle 4 = 120^o$
$\angle 2 = \angle 4 = 120^o$ (Alternate angles are equal)
Hence, $\angle 2 =120^o$.
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