In the figure, find $x$, further find $\angle BOC, \angle COD$ and $\angle AOD$."

To do:

We have to find $x$ and $\angle BOC, \angle COD$ and $\angle AOD$.

Solution:

We know that,

Linear pairs of angles add up to 180 degrees.

In the given figure, $\angle AOD$ and $\angle BOD$ form a linear pair.

Therefore,

$(x+10)^o+[x^o+(x+20^o)]=180^o$                  [$\angle BOD=\angle BOC+\angle COD$]

$3x=180^o-10^o-20^o$

$3x=150^o$

$x=50^o$

$\angle BOC=x+20^o=50^o+20^o=70^o$

$\angle COD=x=50^o$

$\angle AOD=x+10^o=50^o+10^o=60^o$

The value of $x$ is $50^o$.  

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Simply Easy Learning

Updated on: 10-Oct-2022

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