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In the figure, find the value of $x$."
Given:
$\angle BOF=5x, \angle AOC=3x, \angle DOE=2x$
To do:
We have to find the value of $x$.
Solution:
We know that,
Vertically opposite angles are equal.
Sum of the angles on a straight line is $180^o$.
Therefore,
$\angle DOB=\angle AOC=3x$ (Vertically opposite angles)
$FOE$ is a straight line.
This implies,
$\angle BOF+\angle BOD+\angle DOE = 180^o$
$5x + 3x + 2x = 180^o$
$10x= 180^o$
$x=\frac{180^o}{10}$
$x=18^o$
Hence, $x = 18^o$.
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