In the figure, $\angle 1 = 60^o$ and $\angle 2 = (\frac{2}{3})$rd a right angle. Prove that $l \parallel m$."

Given:

$\angle 1 = 60^o$ and $\angle 2 = (\frac{2}{3})$rd a right angle.
To do:

We have to prove that $l \parallel m$.

Solution:

In the given figure,

Transversal $n$ intersects two lines $l$ and $m$.

$\angle 1 = 60^o$

$\angle 2 = (\frac{2}{3})90^o$

$=60^o$

This implies,

$\angle 1 = \angle 2$

$\angle 1$ and $\angle 2$ are corresponding angles

Therefore,

$l \parallel m$.

Hence proved.

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Updated on: 10-Oct-2022

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