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In the below figure, $ O A B C $ is a square of side $ 7 \mathrm{~cm} $. If $ O A P C $ is a quadrant of a circle with centre O, then find the area of the shaded region. (Use $ \pi=22 / 7 $ )"
Given:
\( O A B C \) is a square of side \( 7 \mathrm{~cm} \).
\( O A P C \) is a quadrant of a circle with centre O.
To do:
We have to find the area of the shaded region.
Solution:
Length of the side of the square $=7\ cm$
Area of the square $= (7)^2$
$= 49\ cm^2$
Radius of the quadrant $= 7\ cm$
Therefore,
Area of the quadrant $=\frac{1}{4} \pi r^{2}$
$=\frac{1}{4} \times \frac{22}{7} \times 7^2$
$=\frac{77}{2}$
$=38.5 \mathrm{~cm}^{2}$
Area of the shaded region $=$ Area of the square $-$ Area of the quadrant
$=49-38.5$
$=10.5 \mathrm{~cm}^{2}$
The area of the shaded region is $10.5\ cm^2$.
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