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In the adjoining figure, $ P Q=R S $ and $ Q R= $ SP. Find the third pair of corresponding parts that makes $ \Delta P Q R \cong \Delta $ PSR."
Given:
$PQ=RS$ and $QR=SP$
To do:
We have to find the third pair of corresponding parts that makes \( \Delta P Q R \cong \Delta \) PSR.
Solution:
In the above figure,
$PQ=RS$ (given)
$QR=SP$ (given)
$PR =PR$ (common side)
Therefore,
\( \Delta P Q R \cong \Delta \) PSR (By SSS congruency)
The third pair of corresponding parts that makes \( \Delta P Q R \cong \Delta \) PSR is $PR=PR$.
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