In order to obtain a magnification of, $-$3 (minus 3) with a convex lens, the object should be placed:(a) between optical centre and F (b) between F and 2F(c) at 2F (d) beyond 2F
(b) Between F and 2F
Explanation
Since, the magnification of the image is negative, it means the nature of the image is real and inverted. Also, size of the image is more than 1 which is 3, it implies that the size of the image is magnified (enlarged).
Thus, the image of this nature and size is formed when the object is placed between $F'$ and $2F'$ of a convex lens.
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