In order to obtain a magnification of, −0.6 (minus 0.6) with a concave mirror, the object must be placed:- at the focus
- between pole and focus
- between focus and centre of curvature
- beyond the centre of curvature
(d) beyond the centre of curvature
Explanation
Given:
Magnification, $m$ =$-$0.6
Here, magnification is with the positive sign $(-)$, which implies that the image is real and inverted.
$\because m
In the case of the concave mirror, both of the above-mentioned conditions are only possible when the object is placed beyond the centre of curvature $(C)$ in front of the mirror.
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