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In how many years does the sum of ₹1200 become ₹1800 at the rate of simple interest of 5% per annum?
Given :
Principal (P)$= ₹1200$.
Amount (A)$= ₹1800$.
Rate of interest (R)$=5$%.
To do :
We have to find the time period.
Solution :
Simple interest $= \frac{PnR}{100}$
Simple interest $=$ Amount $-$ Principal.
$ = 1800 - 1200 = 600$.
$600 = \frac{1200 \times n \times 5}{100}$
$\frac{600\times 100}{1200 \times 5} = n$
$n = \frac{100}{2 \times 5}$
$n = \frac{100}{10}$
$n = 10$
Therefore, the time period is 10 years.
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