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# In how many years does the sum of Ã¢â€šÂ¹1200 become Ã¢â€šÂ¹1800 at the rate of simple interest of 5% per annum?

**Given :**

Principal (P)$= â‚¹1200$.

Amount (A)$= â‚¹1800$.

Rate of interest (R)$=5$%.

**To do :**

We have to find the time period.

**Solution :**

Simple interest $= \frac{PnR}{100}$

Simple interest $=$ Amount $-$ Principal.

$ = 1800 - 1200 = 600$.

$600 = \frac{1200 \times n \times 5}{100}$

$\frac{600\times 100}{1200 \times 5} = n$

$n = \frac{100}{2 \times 5}$

$n = \frac{100}{10}$

$n = 10$

**Therefore, the time period is 10 years.**

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