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In an isosceles triangle, the vertex angle is twice either base angle. Find the angles, and represent the situation as an equation.
Given:
In an Isosceles triangle, the vertex angle is twice either base angle.
To do :
We have to find the angles and represent the situation as an equation.
Solution :
Let each base angle be b°.
This implies,
The measure of the vertex angle $= 2(b)° = 2b°$
We know that,
The sum of the angles in a triangle is 180°.
Therefore,
$b°+b°+2b° = 180°$
$4b° = 180°$
$b° =\frac{180°}{4}= 45°$
The measures of the angles are 45°,45° and 90°.
The required equation is $4b°-180° = 0$.
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