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# In an isosceles triangle, the vertex angle is twice either base angle. Find the angles, and represent the situation as an equation.

**Given:**

In an Isosceles triangle, the vertex angle is twice either base angle.

**To do :**

We have to find the angles and represent the situation as an equation.

**Solution :**

Let each base angle be b°.

This implies,

The measure of the vertex angle $= 2(b)° = 2b°$

We know that,

The sum of the angles in a triangle is 180°.

Therefore,

$b°+b°+2b° = 180°$

$4b° = 180°$

$b° =\frac{180°}{4}= 45°$

**The measures of the angles are 45°,45° and 90°**.

**The required equation is $4b°-180° = 0$.**

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