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In an isosceles triangle, the base angles are equal. The vertex angle is 50°. What are the base angles of the triangle?
Given:
In an isosceles triangle, the base angles are equal.
The vertex angle is 50°.
To do:
We have to find the measure of the base angles of the triangle.
Solution:
Let the measure of each base angle be x.
We know that,
Sum of the angles in a triangle is 180°.
Therefore,
$x+x+50° = 180°$
$2x = 180°-50°$
$2x=130°$
$x=\frac{130°}{2}$
$x = 65°$
Therefore, the measure of each of the base angles is 65°.
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