In an examination , a student has to score 40%marks to pass. He gets 40 marks and fail by 40 marks. Find the maximum number of marks

Given: In an examination , a student has to score $40$ % marks to pass. He gets $40$ marks and fail by $40$ marks.

To do: To find the maximum number of marks.

Solution:

Let $x$ be the total marks.

$\Rightarrow x=80\times\frac{100}{40}$

$\Rightarrow x=\frac{8000}{40}$

$\Rightarrow x=\frac{800}{4}$

$\Rightarrow x=200$
 

Thus, maximum number of marks is $200$.

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Updated on: 10-Oct-2022

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