In an A.P., if $a = 3.5,\ d = 0,\ n = 101$, then find $a_n$.
Given: In an AP, if $a = 3.5,\ d = 0,\ n = 101$.
To do: To find $a_n$.
Solution:
As given, $a = 3.5,\ d = 0,\ n = 101$
$\therefore a_n=a+( n-1)d$
$\Rightarrow a_n=3.5+( 101-1)0$
$\Rightarrow a_n=3.5+0$
$\Rightarrow a_n=3.5$
Thus, $a_n=3.5$.
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