In an A.P. first two terms are 12,16 then find its $25^th$ term.
Given: In an A.P. first two terms are $12,\ 16$.
To do: To find its $25^{th}$ term.
Solution:
Here, first term $a=12,$ and common difference $d=16-12=4$
As known that $n^{th}\ term\ t_n=a+(n-1)d$
$\Rightarrow t_{25}=12+( 25-1)4$
$\Rightarrow t_{25}=12+24\times4$
$\Rightarrow t_{25}=12+96=108$
Thus, $25^{th}$ term of the A.P. is $108$.
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