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# In a two digit number, the digit in the units place is twice the digit in tens place. If 27 is added to it digit are reversed . Find the number.

**Given:**In a two digit number digit in units place is twice the digit in the tens place. $27$ is added, then its digits are reversed.

**To do:**To find the number.

**Solution:**

Let ten's digit $=x$

Unit's digit $=2x$

Required Number $=10x+2x=12x$

On Interchanging the Digit's Number $=10( 2x)+x=21x$

According to The Question

$\Rightarrow 12x+27=21x$

$\Rightarrow 21x-12x=27$

$\Rightarrow 9x=27$

$\Rightarrow x=\frac{27}{9}$

$\Rightarrow x=3$

$\therefore$ Number$=12\times3=36$

Hence, the number required number is 36.

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