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In a triangle locate a point in its interior which is equidistant from all the sides of the triangle.
To do:
In a triangle locate a point in its interior which is equidistant from all the sides of the triangle.
Solution:
Let us consider a $\triangle ABC$
We know that,
A point in the interior of the triangle, equidistant from all the sides of the triangle will be its Incenter.
The incenter of a triangle is the point of intersection of all the three interior angle bisectors of the triangle.
Therefore,
In order to locate incentre of $\triangle ABC$
Let us draw three interior angle bisectors from points $A$, $B$ and $C$.
Let us mark the point of intersection as point $O$.
Therefore, $O$ is the point in its interior which is equidistant from all the sides of the triangle.
Updated on: 10-Oct-2022
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