In a $\triangle ABC$, if $\angle B = \angle C = 45^o$. Which is the longest side?
Given:
In $\triangle ABC$, $\angle B = \angle C = 45^o$.
To do:
We have to determine the longest side of the triangle.
Solution:
We know that,
Sum of the angles in a triangle is $180^o$.
Therefore,
$\angle A +\angle B +\angle C =180^o$
$\angle A+45^o+45^o=180^o$
$\angle A=180^o-90^o$
$\angle A=90^o$
$\angle A$ is the greatest angle. This implies side $BC$ which is opposite to the greatest angle is the longest side.
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