In a reaction, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g of water, and 8.2 g of sodium ethanoate. Show that these observations are in agreement with the law of conservation of mass carbonate.

Sodium carbonate + Ethanoic acid $\rightarrow$ Sodium ethanoate + carbon oxide + water

  5.3g          +        6g              $\rightarrow$   8.2 g      +      2.2 g            + 0.9g

                  LHS = RHS

Therefore, 11.3g = 11.3g

(Mass of reactant) (Mass of product)

This shows that during a chemical reaction mass of reactant = mass of product.

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Updated on: 14-Mar-2023

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