In a quadrilateral $ABCD$, the angles $A, B, C$ and $D$ are in the ratio $1 : 2 : 4 : 5$. Find the measures of each angle of the quadrilateral.
Given:
In a quadrilateral $ABCD$, the angles $A, B, C$ and $D$ are in the ratio $1 : 2 : 4 : 5$.
To do:
We have to find the measures of each angle of the quadrilateral.
Solution:
We know that,
Sum of the angles in a quadrilateral is $360^o$.
Let the angles $A, B, C$ and $D$ be $x, 2x, 4x$ and $5x$ respectively.
Therefore,
$x+2x+4x+5x=360^o$
$12x=360^o$
$x=\frac{360^o}{12}$
$x=30^o$
This implies,
$2x=2(30^o)=60^o$
$4x=4(30^o)=120^o$
$5x=5(30^o)=150^o$
Hence, the measures of each angle of the quadrilateral are $30^o, 60^o, 120^o$ and $150^o$.
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