In a parallelogram $ABCD$, if $\angle B = 135^o$, determine the measures of its other angles.
Given:
In a parallelogram $ABCD$, $\angle B = 135^o$.
To do:
We have to determine the measures of its other angles.
Solution:
We know that,
The Sum of two consecutive angles of a parallelogram is $180^o$.
Opposite angles of a parallelogram are equal.
Therefore,
$\angle A + \angle B = 180^o$
$\angle A + 135^o = 180^o$
$\angle A = 180^o-135^o$
$\angle A = 45^o$
$\angle C = \angle A = 45^o$
$\angle D = \angle B = 135^o$
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