In a parallelogram $ABCD, \angle D = 135^o$, determine the measure of $\angle A$ and $\angle B$.
Given:
In a parallelogram $ABCD, \angle D = 135^o$.
To do:
We have to determine the measure of $\angle A$ and $\angle B$.
Solution:
We know that,
Opposite angles of a parallelogram are equal.
Adjacent angles of a parallelogram are supplementary
Therefore,
$\angle B=\angle D=135^o$ (Opposite angles)
$\angle A+\angle B=180^o$
$\angle A+135^o=180^o$
$\angle A=180^o-135^o$
$\angle A=45^o$
Hence, $\angle A=45^o$ and $\angle B=135^o$.
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