# In a family of $3$ children calculate the probability of having at least one boy.

**Given:** There are $3$ children in a family.

**To do:** To find the probability of getting at least one boy.

**Solution:**

Let, boy-B and girl -G

so the total outcomes are:

[GGG, GBB, GBG, GGB, BGG, BBG, BBB, BGB]

Favorable outcomes to be a boy are:

[GBB, GBG, GGB, BGG, BBG, BBB, BGB]

Total no. of possible outcomes$=8$

Total no. of favorable outcomes $= 7$

Probability of getting at least 1 boy $=\frac{Total\ no.\ of\ favorable\ outcomes}{Total\ no.\ of\ possible\ outcomes}=\frac{7}{8}$

Thus the probability of getting atleast one boy in a family is $\frac{7}{8}$.

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