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In 10 s, a charge of 25C leaves a battery, and 200J of energy are delivered to an outside circuit as a result.a) What is the PD across the battery?b) What current flows from the battery?
Given: The charge of a battery = 25C
The time through which the charge flowed = 10s
Energy delivered = 200J
a) To find: We have to find the Potential Difference across a battery.
Solution: We know that, $v=\ \frac{W}{ \begin{array}{l}
Q\\
\end{array}}$
=> $v=\ \frac{200}{ \begin{array}{l}
25\\
\end{array}}$
=> v = 8 volts.
b) To find: We have to find the current flowing through the battery.
Solution: We know that,
$I=\ \frac{Q}{ \begin{array}{l}
t\\
\end{array}}$
=> $I=\ \frac{25}{ \begin{array}{l}
10\\
\end{array}}$
=> $I=\ \frac{25}{ \begin{array}{l}
10\\
\end{array}}$
=> I = 2.5A
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