In 10 s, a charge of 25C leaves a battery, and 200J of energy are delivered to an outside circuit as a result.a) What is the PD across the battery?b) What current flows from the battery?

Given: The charge of a battery = 25C

The time through which the charge flowed = 10s

Energy delivered = 200J

a) To find: We have to find the Potential Difference across a battery.

Solution: We know that, $v=\ \frac{W}{ \begin{array}{l}
Q\\
\end{array}}$

=> $v=\ \frac{200}{ \begin{array}{l}
25\\
\end{array}}$

=> v = 8 volts.

b) To find: We have to find the current flowing through the battery.

Solution: We know that,

$I=\ \frac{Q}{ \begin{array}{l}
t\\
\end{array}}$

=> $I=\ \frac{25}{ \begin{array}{l}
10\\
\end{array}}$

=> $I=\ \frac{25}{ \begin{array}{l}
10\\
\end{array}}$

=> I = 2.5A 
 

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Updated on: 10-Oct-2022

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