If three coins are tossed simultaneously, then write their outcomes.$( a)$. All possible outcomes.
$( b)$. Number of possible outcomes.
$( c)$. Find the probability of getting at least one head.
$( d)$. Find the Probability of getting at most two heads.
$( e)$. Find the Probability of getting no tails.

Given: Three coins are tossed simultaneously.

To do: To write their outcomes and to find:

$( a)$. All possible outcomes.

$( b)$. Number of possible outcomes.

$( c)$. Find the probability of getting at least one head.

$( d)$. Find the Probability of getting at most two heads.

$( e)$. Find the Probability of getting no tails

Solution:

While tossing three coins simultaneously outcomes are:

 {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}

$( a)$. Then all possible outcomes are $=8$

$( b)$. Then number of possible outcomes$=8$

$( c)$. Then the probability of getting at least one head$=\frac{number\ of\ possible\ outcomes\ of\ one\ heads}{number\ of\ total\ possible\ outcomes}=\frac{3}{8}$

$( d)$. Then the probability of getting at least two heads$=\frac{number\ of\ possible\ outcomes\ of\ two\ heads}{ number\ of\ total\ possible\ outcomes}=\frac{3}{8}$

$( e)$. Then the probability of getting no tail$=\frac{number\ of\ possible\ outcomes\ of\ no\  tail}{ number\ of\ total\ possible\ outcomes}=\frac{1}{8}$