If the time of station A is 6:30 pm, $90^o$ E. Find the time of station B, $60^o$E.
Given:
The time of station A is 6:30 pm, $90^o$ E.
To do:
We have to find the time of station B at $60^o$ E.
Solution:
We know that,
Time changes by 4 minutes every degree. It increases from west to east and it decreases from east to west.
Therefore,
Change in the degree latitude from station B and station A $=90^o-60^o=30^o$.
Change in time $=4\times30=120$ minutes $=\frac{120}{60}\ hr=2\ hr$
Time of station B at $60^o$ E $=6:30-2:00=4:30$
The time at station B is 4:30 pm.
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