If the sum of zeroes of the quadratic polynomial $3x^2–kx+6$ is $3$, then find the value of $k$.
Given: The sum of zeroes of the quadratic polynomial $3x^2–kx+6$ is $3$.
To do: To find the value of $k$.
Solution:
Given polynomial: $3x^2–kx+6$
The sum of the zeroes of the polynomial $3=-\frac{b}{a}$
$\Rightrarrow 3=-\frac{-k}{3}$
$\Rightarrow 3=\frac{k}{3}$
$\Rightarrow k=9$
Thus the value of $k=9$.
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