If the sides of a triangle are 3 cm, 4 cm, and 6 cm long, determine whether the triangle is a right-angled triangle.
Given:
The sides of a triangle are $3\ cm, 4\ cm$, and $6\ cm$ long.
To do:
We have to determine whether the triangle is a right-angled triangle.
Solution:
Let the sides of the triangle be,
$AB=3\ cm$
$BC=4\ cm$
$CA=6\ cm$
We know that,
If the square of the hypotenuse is equal to the sum of the squares of the other two sides, then the triangle is a right-angled triangle.
Therefore,
$(AB)^2=(3\ cm)^2=9\ cm^2$
$(BC)^2=(4\ cm)^2=16\ cm^2$
$(CA)^2=(6\ cm)^2=36\ cm^2$
Here, $(AB)^2+(BC)^2=(9+16)\ cm^2=25\ cm^2$
$(AB)^2+(BC)^2≠ (CA)^2$
Therefore, by the converse of Pythagoras theorem, the given sides cannot be the sides of a right triangle.
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