If the point $ (3,4) $ lies on the graph of the equation $ 3 y=a x+7 $, find the value of $ a $.
Given:
The point $(3, 4)$ lies on the graph of the equation $3y=ax+7$.
To do:
We have to find the value of $a$.
Solution:
According to the question,
$(x, y)=(3, 4)$
Now, by substituting $(x, y)=(3, 4)$ in the equation
We get,
$3(4)=a(3)+7$
This implies,
$12=3a+7$
$12-7=3a$
$5=3a$
$3a=5$
$a=\frac{5}{3}$
Therefore,
The value of $a$ is $\frac{5}{3}$.
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