If the list price of a toy is reduced by Rs. 2, a person can buy 2 toys more for Rs. 360. Find the original price of the toy.
Given:
If the list price of a toy is reduced by Rs. 2, a person can buy 2 toys more for Rs. 360.
To do:
We have to find the original price of the toy.
Solution:
Let the original price of the toy be $Rs. x$.
This implies,
Number of toys he can buy at the original price $=Rs. \frac{360}{x}$.
Price of the toy when reduced by $Rs. 2 = Rs. x-2$.
Therefore,
$\frac{360}{x-2}=2+\frac{360}{x}$
$\frac{360}{x-2}=\frac{2x+360}{x}$
$360(x)=(2x+360)(x-2)$
$360x=2x^2-4x+360x-720$
$2x^2-4x-720=0$
$2(x^2-2x-360)=0$
$x^2-2x-360=0$
Solving for $x$ by factorization method, we get,
$x^2-20x+18x-360=0$
$x(x-20)+18(x-20)=0$
$(x+18)(x-20)=0$
$x+18=0$ or $x-20=0$
$x=-18$ or $x=20$
Therefore, the value of $x$ is $20$. ($x$ cannot be negative)
The original price of the toy is $Rs. 20$.
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