,p>If the length and breadth of a rectangle are doubled, by what percentage is it's area increased
Given:
The length and breadth of a rectangle are doubled.
To do:
We have to find the percentage increase in the area.
Solution:
Let the original length of the rectangle be $l$ and the breadth be $b$.
Area of the original rectangle $=lb$.
The length and breadth of the rectangle are doubled.
This implies,
New length $=2l$
New breadth $=2b$
The area formed by the new rectangle $=(2l)(2b)$
$=4lb$
Increase in the area $=4lb-lb$
$=3lb$
Percentage increase in the area $=\frac{3lb}{lb}\times100 \%$
$=3\times100 \%$
$=300 \%$
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