,p>If the length and breadth of a rectangle are doubled, by what percentage is it's area increased


Given:

The length and breadth of a rectangle are doubled.

To do:

We have to find the percentage increase in the area.

Solution:

Let the original length of the rectangle be $l$ and the breadth be $b$. 

Area of the original rectangle $=lb$.

The length and breadth of the rectangle are doubled.

This implies,

New length $=2l$

New breadth $=2b$

The area formed by the new rectangle $=(2l)(2b)$

$=4lb$

Increase in the area $=4lb-lb$

$=3lb$

Percentage increase in the area $=\frac{3lb}{lb}\times100 \%$

$=3\times100 \%$

$=300 \%$

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Updated on: 10-Oct-2022

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