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If the length and breadth of a rectangle are $ 10 \mathrm{~cm} $ and $ 20 \mathrm{~cm} $, respectively, find the length of its diagonal.
Given:
The length and breadth of a rectangle are \( 10 \mathrm{~cm} \) and \( 20 \mathrm{~cm} \).
To do:
We have to find the length of its diagonal.
Solution:
We know that,
Length of the diagonal of a rectangle of length $l$ and breadth $b$ is $\sqrt{l^2+b^2}$
The length of the rectangle $=10\ cm$
The breadth of the rectangle $=20\ cm$
Therefore,
The length of the diagonal $=\sqrt{(10)^2+(20)^2}$
$=\sqrt{100+400}$
$=\sqrt{500}$
$=\sqrt{5\times100}$
$=2.236\times10$
$=22.36\ cm$
The length of the diagonal of the given rectangle is $22.36\ cm$.
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