If the charge of an electron is 1.6 x 10^-19 coulombs, how many electrons should pass through a conductor in 1 second to constitute a 1-ampere current?

Given: The charge of an electron = 1.6 x 10-19 coulombs

To find: We have to find how many electrons are passing through a conductor in 1sec to constitute a 1-ampere current.

 
 Solution:

We know that 1C =1A x 1 s

=> Q = 1C.

Now,

Q = ne

=> 1 = n x 1.6 x 10-19  

=> n = $I=\ \frac{1}{ \begin{array}{l}
1.6\ \times \ 10^{-19}\\
\end{array}}$

=> n = 6.25 x 10¹⁸

Therefore, the number of electrons is 6.25 x 10¹⁸

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Updated on: 10-Oct-2022

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