If the angles of a quadrilateral are $4x, 3x+10^o, 2x+10^o$ and $4x+15^o$, then find the angles.
Given:
The given angles of the quadrilateral are $4x, 3x+10^o, 2x+10^o$ and $4x+15^o$.
To do:
We have to find the angles.
Solution:
We know that,
Sum of the angles in a quadrilateral is $360^o$.
$4x+3x+10^o+2x+10^o+4x+15^o=360^o$
$13x+35^o=360^o$
$13x=360^o-35^o$
$13x=325^o$
$x=\frac{325^o}{13}$
$x=25^o$
$4x=4(25^o)=100^o$
$3x+10^o=3(25^o)+10^o=75^o+10^o=85^o$
$2x+10^o=2(25^o)+10^o=50^o+10^o=60^o$
$4x+15^o=4(25^o)+15^o=100^o+15^o=115^o$
The angles of the quadrilateral are $60^o, 85^o, 100^o$ and $115^o$.
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