If the angles $(2x - 10)^o$ and $(x - 5)^o$ are complementary angles, find $x$.

Given:

The angles $(2x - 10)^o$ and $(x - 5)^o$ are complementary angles.

To do:

We have to find $x$.

Solution:

Two angles are said to be complementary if the sum of their measures is $90^o$.

Therefore,

$(2x-10)^o+(x-5)^o=90^o$

$2x+x-10^o-5^o=90^o$

$3x=90^o+15^o$

$3x=105^o$

$x=\frac{105^o}{3}$

$x=35^o$

The value of $x$ is $35^o$. 

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Updated on: 10-Oct-2022

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