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If $tan\theta +cot\ \theta =5$, then find the value of $tan^{2} \theta +cot^{2} \theta $.
Given: $tan\theta +cot\theta =5$.
To do: To find the value of $tan^{2} \theta +cot^{2} \theta $.
Solution: As given, $tan\theta +cot\theta =5$
On squaring both sides,
$( tan\theta +cot\theta )^{2} =5^{2}$
$\Rightarrow tan^{2} \theta +cot^{2} \theta +2tan\theta cot\theta =25$
$\Rightarrow tan^{2} \theta +cot^{2} \theta +2=25$
$\Rightarrow tan^{2} \theta +cot^{2} \theta =25-2$
$\Rightarrow tan^{2} \theta +cot^{2} \theta =23$
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