If $ \sqrt{2}=1.414, \sqrt{5}=2.236 $ and $ \sqrt{3}=1.732, $ find the value of:
(i) $ \sqrt{72}+\sqrt{48} $
(ii) $ \sqrt{\frac{125}{64}} $

Given:

\( \sqrt{2}=1.414, \sqrt{5}=2.236 \) and \( \sqrt{3}=1.732 \).
To do:

We have to find the value of \( \sqrt{2}=1.414, \sqrt{5}=2.236 \) and \( \sqrt{3}=1.732 \)..
Solution:

(i) $\sqrt{72}+\sqrt{48}=\sqrt{36\times2}+\sqrt{16\times3}$

$=\sqrt{6\times6\times2}+\sqrt{4\times4\times3}$
$=6\sqrt{2}+4\sqrt{3}$
 $=6\times1.414+4\times1.732$

$=8.484+6.928$

$=15.412$

(ii) $\sqrt{\frac{125}{64}}=\sqrt{\frac{5\times5\times5}{8\times8}}$

$=\frac{5}{8}\sqrt{5}$

$=\frac{5}{8}\times2.236$

$=\frac{11.18}{8}$

$=1.3975$

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Updated on: 10-Oct-2022

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