If speed of a car becomes 2 times, its kinetic energy becomes:
(a) 4 times
(b) 8 times
(c) 16 times
(d) 12 times

As known, kinetic energy $K=\frac{1}{2}mv^2$

$K\rightarrow$ Kinetic energy

$m\rightarrow$ mass of the moving car

$v\rightarrow$ speed of the car

If the speed of the car is doubled, then it becomes $2v$.

Then kinetic energy of the car $K'=\frac{1}{2}m(2v)^2$

$=4\frac{1}{2}mv^2$

$=4K$

Thus on doubling the speed of the car, its kinetic energy becomes 4 times.

Therefore, option (a) is correct.

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Updated on: 10-Oct-2022

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