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If $sin\theta+sin^{2}\theta=1$, then evaluate $cos^{2}\theta+cos^{4}\theta$.
Given: $sin\theta+sin^{2}\theta=1$.
To do: To evaluate $cos^{2}\theta+cos^{4}\theta$.
Solution:
As given $sin\theta+sin^{2}\theta=1$
$\Rightarrow sin\theta+1-cos^{2}\theta=1$ [$\because sin^{2}\theta+cos^{2}\theta=1$]
$\Rightarrow sin\theta-cos^{2}\theta=0$
$\Rightarrow sin\theta=cos^{2}\theta$
Now on substituting $sin\theta=cos^{2}\theta$ in $cos^{2}\theta+cos^{4}\theta$
$\Rightarrow cos^{2}\theta+cos^{4}\theta=sin\theta+sin^{2}\theta=1$ [Given $sin\theta+sin^{2}\theta=1$]
$\therefore cos^{2}\theta+cos^{4}\theta=1$
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