If $p=-2$, find the value of:
$(i)$. $4p+7$
$(ii)$. $-3p^2+4p+7$
$iii)$. $-2p^3-3p^2+4p+7$

Given: 

$(i)$. $4p+7$

$(ii)$. $-3p^2+4p+7$

$iii)$. $-2p^3-3p^2+4p+7$

To do: To find the value of if $p=-2$.

Solution: 

$(i)$. $4p+7$

Putting $p=-2$

$=4(-2)+7$

$=-8+7$

$=-1$

$(ii)$. $-3p^2+4p+7$

Putting $p=-2$

$=-3(-2)^2+4(-2)+7$

$=-3(4)-8+7$

$=-12-8+7$

$=-13$

$(iii)$. $-2p^3-3p^2+4p+7$

Putting $p=-2$

$=-2(-2)^3-3(-2)^2+4(-2)+7$

$=-2(-8)-3(4)-8+7$

$=16-12-8+7$

$=3$

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Updated on: 10-Oct-2022

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